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CGP EDU Academic Team
Published on: September 13, 2026
The length of the second pendulum on the surface of earth is 1 m. The length of seconds pendulum on the surface of moon, where g is 1/6th value of g on the surface of earth, is
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A
$T = 2 \pi \sqrt{\frac{l}{g}}$ ⇒ ⇒ $\sqrt{\frac{1}{g}}$ = constant
$\Rightarrow l \propto g$ ; ⇒ ⇒ $\frac{l_m}{1} = \frac{1 \, g}{6 \, g} \Rightarrow l_m = \frac{1}{6} m$
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